Rewriting of ResultsCondition, first part
Allow to give int, float, and not only strings Fix AND/OR conditions Add some comments to unterstand this fucking code
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4dbe7b8c5d
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31016c4846
1 changed files with 24 additions and 13 deletions
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@ -27,14 +27,14 @@ __all__ = ['ResultsCondition', 'ResultsConditionError']
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class ResultsCondition(IResultsCondition):
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condition_str = None
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# TODO: NOT?
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def __init__(self, condition_str):
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condition_str = condition_str.replace(' OR ', ' or ') \
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.replace(' AND ', ' and ') \
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.replace(' NOT ', ' not ')
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condition_str = condition_str.replace(' NOT ', ' not ')
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or_list = []
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for _or in condition_str.split(' or '):
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for _or in condition_str.split(' OR '):
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and_dict = {}
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for _and in _or.split(' and '):
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for _and in _or.split(' AND '):
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if '!=' in _and:
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k, v = _and.split('!=')
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k = k.strip() + '!'
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@ -47,24 +47,35 @@ class ResultsCondition(IResultsCondition):
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self.condition = or_list
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self.condition_str = condition_str
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def is_valid(self, obj):
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d = dict(obj.iter_fields())
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# A and B give us a list with one elements of two dicts ([{u'A': u'toto', u'B': u'charles'}]
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# A or B give us a list with two elements of one dict [{u'A': u'toto'}, {u'B': u'charles'}]
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# We have to return True if one element of the list is True, and to evaluate all dicts at each iteration
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for _or in self.condition:
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myeval = True
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for k, v in _or.iteritems():
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different = False
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if k.endswith('!'):
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k = k[:-1]
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different = True
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else:
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different = False
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if k in d:
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if different:
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if d[k] != v:
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return True
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else:
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if d[k] == v:
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return True
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# We have to change the type of v, always gived as string by application
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typed = type(d[k])
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try:
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myeval = (d[k] == typed(v)) != different
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except:
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myeval = False
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else:
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raise ResultsConditionError(u'Field "%s" is not valid.' % k)
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# Do not try all AND conditions if one is false
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if not myeval:
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break
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# Return True at the first OR valid condition
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if myeval:
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return True
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# If we are here, all OR conditions are False
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return False
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def __str__(self):
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