79 lines
2.3 KiB
C++
79 lines
2.3 KiB
C++
// -*- mode: c++; c-indent-level: 4; c++-member-init-indent: 8; comment-column: 35; -*-
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// "order_xover.cpp"
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// (c) OPAC Team, LIFL, 2002
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/* This library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Lesser General Public
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License as published by the Free Software Foundation; either
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version 2 of the License, or (at your option) any later version.
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This library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public
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License along with this library; if not, write to the Free Software
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Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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Contact: paradiseo-help@lists.gforge.inria.fr
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*/
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#include <assert.h>
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#include <utils/eoRNG.h>
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#include "order_xover.h"
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void OrderXover :: cross (const Route & __par1, const Route & __par2, Route & __child) {
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unsigned cut2 = 1 + rng.random (numNodes) ;
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unsigned cut1 = rng.random (cut2);
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unsigned l = 0;
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/* To store vertices that have already been crossed */
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std :: vector <bool> v (numNodes, false);
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/* Copy of the left partial route of the first parent */
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for (unsigned i = cut1 ; i < cut2 ; i ++) {
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__child [l ++] = __par1 [i] ;
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v [__par1 [i]] = true ;
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}
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/* Searching the vertex of the second path, that ended the previous first one */
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unsigned from = 0 ;
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for (unsigned i = 0; i < numNodes; i ++)
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if (__par2 [i] == __child [cut2 - 1]) {
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from = i ;
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break ;
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}
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/* Selecting a direction (Left or Right) */
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char direct = rng.flip () ? 1 : -1 ;
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for (unsigned i = 0; i < numNodes + 1; i ++) {
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unsigned bidule = (direct * i + from + numNodes) % numNodes;
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if (! v [__par2 [bidule]]) {
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__child [l ++] = __par2 [bidule] ;
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v [__par2 [bidule]] = true ;
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}
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}
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}
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bool OrderXover :: operator () (Route & __route1, Route & __route2) {
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// Init. copy
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Route par [2] ;
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par [0] = __route1 ;
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par [1] = __route2 ;
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cross (par [0], par [1], __route1) ;
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cross (par [1], par [0], __route2) ;
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__route1.invalidate () ;
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__route2.invalidate () ;
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return true ;
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}
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