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allow eoBit to be templatized on its value type

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This helps avoiding the infamous std::vector<bool> specialization,
which (wrongly) exchange space for speed.
This commit is contained in:
Johann Dreo 2020-08-26 11:58:46 +02:00
commit e2bf3ec3c0
1 changed files with 13 additions and 8 deletions
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21
eo/src/ga/eoBit.h
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@ -59,22 +59,27 @@ Example of a complete test program that use various bitstrings operators:
Based on STL's std::vector<bool> specialization.
*/
template <class FitT> class eoBit: public eoVector<FitT, bool>
template <class FitT, class ScalarT = bool>
class eoBit: public eoVector<FitT, ScalarT>
{
public:
using ScalarType = ScalarT;
using eoVector< FitT, bool >::begin;
using eoVector< FitT, bool >::end;
using eoVector< FitT, bool >::resize;
using eoVector< FitT, bool >::size;
using eoVector< FitT, ScalarType >::begin;
using eoVector< FitT, ScalarType >::end;
using eoVector< FitT, ScalarType >::resize;
using eoVector< FitT, ScalarType >::size;
/**
* (Default) Constructor.
* @param size Size of the binary std::string.
* @param value Default value.
*/
eoBit(unsigned size = 0, bool value = false):
eoVector<FitT, bool>(size, value) {}
eoBit(unsigned size = 0, ScalarType value = false):
// eoBit(unsigned size, ScalarType value):
eoVector<FitT, ScalarType>(size, value) {}
/// My class name.
virtual std::string className() const
@ -91,7 +96,7 @@ public:
EO<FitT>::printOn(os);
os << ' ';
os << size() << ' ';
std::copy(begin(), end(), std::ostream_iterator<bool>(os));
std::copy(begin(), end(), std::ostream_iterator<ScalarType>(os));
}
/**